Sunday, September 25, 2016

Electrical sources and loads

By definition, and source is a device that inputs energy into a system, while a load is a device that extracts energy from a system. Examples of typical electrical sources include generators, photovoltaic cells, thermopiles, and primary-cell batteries. Examples of typical electrical loads include resistors, lamps, and electric motors.

In a working circuit, electrical sources and loads may be easily distinguished by comparison of their current directions and voltage drop polarities. An electrical source always manifests a voltage polarity in a direction aiding the direction of charge flow. An electrical source always manifests a voltage polarity in a direction opposing the direction of charge flow.

The way in which we designate the direction of current (charge flow) becomes very important here. Since there are two commonly accepted notations – electron flow and “conventional” flow, exactly opposite of each other – it is easy to become confused.

First we see a diagram showing a source and a load, using electron flow notation. Electrons, being negatively charged particles, are repelled by the negative ( ) poles of both source and load, and attracted to the positive (+) poles of both source and load. The difference between source and load is that the source device motivates the flow of electrons while the load device resists the flow of electrons:







In the case of the source (battery), the polarity of the voltage works for the direction of charge motion. In the case of the load (resistor), the polarity of the voltage drop works against the direction of charge motion.


Next we see a diagram showing the same source and load, this time using “conventional” flow notation to designate the direction of current. Here we must imagine positively-charged carriers moving through the wires instead of electrons. These positive charge carriers are repelled by any positive (+) pole and attracted to any negative ( ) pole. Viewed in this light, we see the exact same principle at work: the source device is seen to motivate the flow of these positive charge carriers while the load device resists the flow:



Despite using a different notation for charge motion, the concept of source and load remains the same. In the case of the source (battery), the polarity of the voltage works for the direction of charge motion. In the case of the load (resistor), the polarity of the voltage drop works against the
direction of charge motion.


An alternative notation for voltage (other than using “+” and “ ” symbols) that many students find particularly illustrative is the use of curved arrows, where the tip of the curved arrow is the positive pole and the tail of the curved arrow is the negative pole. This notation is intended to be used when the direction of current (using “straight” or “angular” arrows) is shown using conventional flow notation:




Using arrows to represent voltage polarity in addition to using arrows to represent current direction is highly intuitive. It shows which way each component in the DC circuit is “pushing” in relation to the flow of charge carriers. Note how the source’s voltage arrow points in the same direction as the current: this means the source is motivating the current, causing charge carriers to flow in this circuit. Note how the resistor’s voltage arrow points opposite to the direction of current: this means the resistor is opposing the current, in a sense “fighting against” the flow of charge carriers. This correspondence of voltage-arrow versus current-arrow direction .

I personally lament the obscurity of this “curved-arrow” notation for voltage, as it greatly aids comprehension of this critically important distinction between sources and loads. When the voltage and current arrows point in the same direction, it means the component in question is motivating charge carriers along and therefore imparts energy to the circuit. When voltage and current arrows point in opposite directions, it means the component in question opposes charge carrier motion and therefore acts to extract energy from the circuit.

This directly relates to the fundamental physics concept of work, specifically in relation to the mathematical sign of work being a function of the relative angle between force and displacement. When a force acts in the same direction as motion, the work done is positive; when a force acts in the opposite direction as motion, the work done is negative:


Positive work represents an infusion of energy into a system (source), while negative work represents an extraction of energy from that system (load).

If we examine a hydraulic system, where a pump pushes fluid around a pipe loop and an orifice (called a “restrictor”) restricts the flow of this fluid, we see this same concept in action: the pump’s pressures at its discharge and suction ports work for the direction of fluid flow, while the pressures at the upstream and downstream ports of the restrictor work against the direction of fluid flow. The pump acts as a power source in this hydraulic “circuit” (infusing energy into the system) while the restrictor acts as a power load (extracting energy from the system):





We may even see this concept revealed in a simple mechanical system where work is being done. Examine the case of a crane lifting a heavy weight into the air, shown below. As the crane lifts the weight upward, the crane’s upward force on the weight is clearly working for the direction of motion, while the weight’s downward force against the crane is clearly working against the direction of motion:




Thus, the crane is doing positive work (acting as a source, infusing potential energy into the weight) while the weight is doing negative work (acting as a load, absorbing potential energy from the crane). A rigorous way to demonstrate this is to calculate the work done by each using the formula W = F.x or W = F * x * cos θ. Since the crane’s force and motion vectors both point in the same direction, θ = 0 and work is a positive quantity F x. The weight’s force vector, however, points 180 away from the motion vector, and so its work calculation is F x cos(180) or F x.






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